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122                                                                                     ICSE Chemistry – 10


                                                and,  Volume of B involved in the reaction =   1   × b units
                                                                                              n
                                                Therefore, the ratio of volumes of the reacting gases A and B is,
                                                                         a  :  b       or     a : b
                                                                         n   n
                                                Since a and b are whole numbers (molecules cannot be in fractions),
                                           hence the volumes of the reacting gases bear a simple whole number
                                           ratio to each other. This is the Gay-Lussac’s law of combining volumes.

                                           How is the atomicity of an elementary gas determined
                                           using Avogadro’s law
                                           To illustrate the determination of the atomicity of an elementary gas, let
                                           us consider the reaction between hydrogen and chlorine to form hydrogen
                                           chloride.
                                                It has been observed experimentally that hydrogen and chlorine react
                 Amedeo Avogadro           in equal volumes. Then, one can write,
                    ;ϭϳϳϲͲϭϴϱϲͿ
           ŵĞĚĞŽ  ǀŽŐĂĚƌŽ ďŽƌŶ ŝŶ dƵƌŝŶ ;/ƚĂůLJͿ  Atomicity of hydrogen and chlorine
          ŽďƚĂŝŶĞĚ ĚĞŐƌĞĞƐ ŝŶ WŚŝůŽƐŽƉŚLJ Ăƚ ƚŚĞ  Hydrogen + Chlorine      o Hydrogen chloride
          ĂŐĞ ŽĨ ϭϯ͕ ŝŶ :ƵƌŝƐƉƌƵĚĞŶĐĞ Ăƚ ϭϲ ĂŶĚ
          ŝŶ  ŚƵƌĐŚ ůĂǁ Ăƚ ϮϬ͘ /Ŷ ϭϴϬϵ͕  ǀŽŐĂĚƌŽ   1 vol         1 vol                 2 vol
          ďĞĐĂŵĞ WƌŽĨĞƐƐŽƌ ŽĨ WŚLJƐŝĐƐ Ăƚ ƚŚĞ    n molecules    n molecules          2n molecules     (Avogadro’s law)
                                                               1
                                                 1
          ZŽLJĂů  ŽůůĞŐĞ Ăƚ sĞƌĐĞůůŝ͘ /Ŷ ϭϴϭϭ͕ ŚĞ  2   molecule      2  molecule      1 molecule
          ƉŽƐƚƵůĂƚĞĚ ŚŝƐ ĨĂŵŽƵƐ ŚLJƉŽƚŚĞƐŝƐ      Since one molecule of hydrogen chloride contains one atom of
          ǁŚŝĐŚŝƐŶŽǁ ŬŶŽǁŶĂƐ ǀŽŐĂĚƌŽ͛Ɛ
          ůĂǁ͘ /Ŷ ϭϴϮϬ͕  ǀŽŐĂĚƌŽ ǁĂƐ ĂƉƉŽŝŶƚĞĚ  hydrogen and one atom of chlorine, hence,
          ƉƌŽĨĞƐƐŽƌ ŽĨ DĂƚŚĞŵĂƟĐĂů WŚLJƐŝĐƐ Ăƚ              1  molecule of hydrogen = 1 atom of hydrogen
          ƚŚĞhŶŝǀĞƌƐŝƚLJŽĨdƵƌŝŶ͘                            2
           ǀŽŐĂĚƌŽ ŝŶ ϭϴϭϭ ƐƵŐŐĞƐƚĞĚ ƚŚĂƚ ƚŚĞ   or,        1 molecule of hydrogen = 2 atoms of hydrogen
          ĂƚŽŵŝĐ ĂŶĚ ŵŽůĞĐƵůĂƌ ŵĂƐƐĞƐ ĐĂŶ ďĞ    Therefore,  Atomicity of hydrogen = 2
          ĞdžƉƌĞƐƐĞĚŽŶĂŶĂƚŽŵŝĐŵĂƐƐƐĐĂůĞ          Similarly,  1  molecule of chlorine = 1 atom of chlorine
          ďĂƐĞĚ ŽŶ ƚŚĞ ĐŽŵƉĂƌŝƐŽŶ ŽĨ ĂƚŽŵŝĐͬ                2
          ŵŽůĞĐƵůĂƌ ŵĂƐƐĞƐ ǁŝƚŚ ƚŚĞ ŵĂƐƐ ŽĨ Ă   or,          1 molecule of chlorine = 2 atoms of chlorine
          ƌĞĨĞƌĞŶĐĞ ĂƚŽŵ͘ /Ŷ ƚŚŝƐ ŵĞƚŚŽĚ͕ ƚŚĞ   Therefore,   Atomicity of chlorine = 2
          ĂƚŽŵŝĐ ŵĂƐƐĞƐ ĂƌĞ ĞdžƉƌĞƐƐĞĚ ƌĞůĂƟǀĞ
          ƚŽ ƚŚĂƚ ŽĨ Ă ƐƚĂŶĚĂƌĚ ƌĞĨĞƌĞŶĐĞ ĂƚŽŵ͘  Thus, the atomicity of both hydrogen and chlorine is two.
           ĂƌůŝĞƌ͕ ŚLJĚƌŽŐĞŶ ĂŶĚ ŽdžLJŐĞŶ ĂƚŽŵƐ
          ǁĞƌĞ ƵƐĞĚ ĂƐ ƚŚĞ ƌĞĨĞƌĞŶĐĞ ĂƚŽŵƐ ĨŽƌ  Atomicity of nitrogen and oxygen
          ĚĞƐĐƌŝďŝŶŐ ĂƚŽŵŝĐ ŵĂƐƐĞƐ͘ /Ŷ ϭϵϱϳ͕  Similarly, we can determine the atomicity of nitrogen and oxygen.
          KůĂŶĚĞƌ ĂŶĚ EŝĞƌ ƉƌŽƉŽƐĞĚ ĂŶ ĂƚŽŵŝĐ
          ŵĂƐƐ ƐĐĂůĞ ďĂƐĞĚ ŽŶ ƚŚĞ ĐŚŽŝĐĞ ŽĨ     Nitrogen    +  Oxygen     o       Nitric oxide
                                   ϭϮ
          ĐĂƌďŽŶͲϭϮ ŝƐŽƚŽƉĞ͕ ;ĚĞƐŝŐŶĂƚĞĚ ĂƐ  ͕     1 vol         1 vol                 2 vol
                                    ϲ
                 ϭϮ
          ƐŝŵƉůLJ ĂƐ  Ϳ͘                         n molecules    n molecules          2n molecules     (Avogadro’s law)
                                                 1   molecule      1   molecule      1 molecule
                                                 2             2
                                                  1 atom         1 atom              1 molecule
                                                Thus,       1  molecule of nitrogen = 1 atom of nitrogen
                                                            2
                                                            1 molecule of nitrogen = 2 atoms of nitrogen
                                                Therefore,  Atomicity of nitrogen = 2
                                                Also,        1  molecule of oxygen = 1 atom of oxygen
                                                             2
                                                             1 molecule of oxygen = 2 atoms of oxygen

                                                Therefore,    Atomicity of oxygen =2
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