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Mole Concept and Stoichiometry                                                                       123

          How is the relationship between molecular mass and
          vapour density derived from Avogadro’s law
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          of a certain volume of gas, to the mass of the same volume of hydrogen gas
          under similar condition of temperature and pressure. Thus,

                                                       Mass of V mL of the substance in gaseous state
                       Vapour density of a substance =
                                                     Mass of V mL of hydrogen under similar conditions
          According to the Avogadro’s law equal volumes of gases under similar
          conditions should contain equal number of molecules. So, if V mL of any
          gas contain n molecules, then
                                   Mass of n molecules of the gaseous substance
                 V.D. of a substance =
                                         Mass of n molecules of hydrogen
                                    Mass of 1 molecule of the gaseous substance
          or      V.D. of a substance =
                                         Mass of 1 molecule of hydrogen
          Since, one molecule of hydrogen contains 2 atoms, hence
                                    Mass of 1 molecule of the gaseous substance
                                           V.D. =
                                         2 × Mass of 1 atom of hydrogen
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                Molecular mass of   Mass of 1 molecule of the gaseous substance
                    the substance  =       Mass of 1 atom of hydrogen

          Hence,

                    Molecular mass of the substance  = 2 × V.D. of the substance
          In general, therefore,
                                    Molecular mass  = 2 × Vapour density

          How to determine the molecular formula of a gaseous
          compound
          The Avogadro’s law can also be used for determining the molecular formula
          of a gaseous compound, if the volumes of the reactants and products
          are known. This is illustrated by taking example of the reaction between
          nitrogen and hydrogen gases to form ammonia. Experimentally, it is found
          that one volume of nitrogen reacts with three volumes of hydrogen to form
          two volumes of ammonia. Then, one can write,
               Nitrogen   + Hydrogen o            Ammonia
                  1 vol         3 vol                 2 vol
               n molecules   3n molecules          2n molecules     (Avogadro’s law)
                1             1
                  molecule       molecule           1 molecule
                2             2
          or     1 atom        3 atom               1 molecule    (atomicity of nitrogen
                                                                     and hydrogen = 2)
              Thus, one molecule of ammonia contains one atom of nitrogen and
          three atoms of hydrogen. Therefore, the molecular formula of ammonia is
          NH .
             3
          Some Examples Based on Avogadro’s Law

          EXAMPLE 5.10.  100 mL of a gas ‘A’ contains x molecules. How many molecules
          of the gas ‘B’ will be present in 50 mL of ‘B’ under same conditions of temperature
          and pressure?
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