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128                                                                                     ICSE Chemistry – 10

                                           How to calculate the atomic mass of an element from the
                                           mass numbers of its isotopes
                                           The atomic mass of an element is the weighted arithmetic mean of the
                                           atomic masses of its isotopes present in the sample of the element.
                                                Let us consider a sample of an element X containing its two isotopes
                                           X  and X . Then
                                                   2
                                            1
                                         (Percentage of X  × Mass number of X ) + (Percentage of X  × Mass number of X )
           Atomic mass of the element X =               1                   1                 2                   2
                                                                             100

                                                This method is illustrated by taking the case of chlorine. The two
                                                                       37
                                                               35
          DĂƐƐ ŶƵŵďĞƌƐ ĂƌĞ ǁŚŽůĞ ŶƵŵďĞƌƐ͕   isotopes of chlorine,  Cl and  Cl occur in the ratio 3 : 1. Then,
                                                                       17
                                                               17
          ǁŚĞƌĞĂƐ ĂƚŽŵŝĐ ŵĂƐƐĞƐ ĂƌĞ ŐĞŶĞƌĂůůLJ
          ĨƌĂĐƟŽŶĂů͘                                               (35 u × 3) + (37 u × 1)  105 u + 37u  142 u
                                           Atomic mass of chlorine =                   =             =       = 35.5 u
                                                                          3 + 1              4          4
                                                                                                        79
                                           EXAMPLE 5.14.  If bromine occurs in the form of say two isotope  Br (49.7%)
                                                                                                        35
                                               81
                                           and  Br (50.3%), then calculate the atomic mass of bromine atom.
                                               35
                                                                            79 u × 49.7 + 81 u × 50.3
                                           Solution: Atomic mass of bromine =                     = 80.0 u
                                                                                  49.7 + 50.3
                                           So, the atomic mass of bromine is 80.0 u.
                                           EXAMPLE 5.15.  The atomic mass of a sample of an element X is 16.2 u. What
                                                                      16
                                                                             18
                                           are the percentages of isotope  X and  X in the sample?
                                                                              8
                                                                       8
                                           Solution: Atomic mass of X = 16.2 u
                                                                        16
                                           Let the percentage of the isotope  X be P . Then,
                                                                         8
                                                                               1
                                                                 18
                                           Percentage of the isotope  X = (100 – P )
                                                                  8
                                                                             1
                                           We can then write,
                                                                                                       16
                                                                          16
                                            Atomic mass of   (Percentage of  X × 16 u) + (100 – Percentage of  X) × 18 u
                                                the sample  =              8         100                8
                                                            (P  × 16 u) + (100 – P ) × 18 u
                                                    16.2 u =  1                1
                                                                        100
                                                    1620 u  = 16 P  u + 1800 u – 18 P  u
                                                                                1
                                                                1
                                                    This gives,
                                                             (18 P  u – 16 P  u)  = 1800 u – 1620 u
                                                                         1
                                                                 1
                                                                       2 P  u  = 180 u
                                                                          1
                                                                               180
                                                                          P  =      = 90
                                                                            1
                                                                                2
                                                                         16
                                                    Thus,    Percentage of X = 90%
                                                                          8
                                                                         18
                                                    and      Percentage of X  = (100 – 90)% = 10%
                                                                          8
                                           Molecular Mass and Relative Molecular Mass
                                           What is the molecular mass of a substance
                                           Average mass of a molecule of any substance is known as its molecular
                                           mass. Molecular mass is designated as M. Since molecular mass is actual
                                           mass, hence it has the unit of mass, viz., gram, kilogram, atomic mass unit,
          dŚĞ ŵŽůĞĐƵůĂƌ ŵĂƐƐ ŽĨ Ă ƐƵďƐƚĂŶĐĞ ŝƐ   etc. The accepted standard unit of molecular mass is atomic mass unit
          ĞƋƵĂů ƚŽ ƚŚĞ ƐƵŵ ŽĨ ĂƚŽŵŝĐ ŵĂƐƐĞƐ ŽĨ   (u). 6JWU  VJG OQNGEWNCT OCUU QH C UWDUVCPEG OC[ DG FGſPGF CU HQNNQYU
          Ăůů ƚŚĞ ĂƚŽŵƐ ƉƌĞƐĞŶƚ ŝŶ Ă ŵŽůĞĐƵůĞ ŽĨ   “The average mass of a molecule of a substance expressed in atomic
          ƚŚĂƚ ƐƵďƐƚĂŶĐĞ͘
                                           mass units is termed as its molecular mass.”
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